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5x^2-20x-225=0
a = 5; b = -20; c = -225;
Δ = b2-4ac
Δ = -202-4·5·(-225)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-70}{2*5}=\frac{-50}{10} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+70}{2*5}=\frac{90}{10} =9 $
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